Let the function q be given by q(x) = -2(-3x + 2) and let y be the image of x under q. Find the formula for q-1.

Given:-
[tex]q(x)=-2(-3x+2)[/tex]To find:-
[tex]q^{\prime}(x)[/tex]So now ,
[tex]y=-2(-3x+2)[/tex]So now we find the value of x. so we get,
[tex]\begin{gathered} y=-2(-3x+2) \\ y=6x-4^{} \\ y+4=6x \\ \frac{y+4}{6}=x \end{gathered}[/tex]So the required solution is,
[tex]q^{\prime}(x)=\frac{y+4}{6}[/tex]