Question

If f(2)=pi+7 then f^-1(pi+7)=?

Answer 1

Hello,

$f(2)=\pi + 7\\\\ 2=f^{-1}\ o\ f(2)=f^{-1} (f(2))=f^{-1}( \pi + 7 })$

Answer 2

Answer: The required value of $f^{'-1}(\pi+7)$ is 2.

Step-by-step explanation:  We are given the following value of a function f :

$f(2)=\pi+7.$

We are to find the value of $f^{-1}(\pi+7).$

We know that

For any function g(x) = y,

$g^{-1}(y)=x.$

Applying the above rule in equation (i), we get

$f(2)=\pi+7\\\\\Rightarrow f^{-1}(\pi+7)=2.$

Thus, the required value of $f^{'-1}(\pi+7)$ is 2.