I just don't know how to solve them this way

we have the system
y=2x^2-3x-1 -----> equation A
Vertical parabola opens upward (the vertex is a minimum)
y=-x-1 -----> equation B
The equation represents the equation of a line with a negative slope
Remember that
When solving a system by graphing, the solutions are the intersection points both graphs
using a graphing tool
see the attached figure below
The solutions are the points
(0,-1) and (1,-2)