Solution
We have the following function:
f(x) = x^2+2 (x >=0)
Part a
Domain:
[tex]\lbrack0,\infty)[/tex]Part b
Range
[tex]\lbrack2,\infty)[/tex]Part c
The inverse function is:
[tex]f^{-1}(x)=\sqrt[]{x-2}[/tex]Domain:
[tex]\lbrack2,\infty)[/tex]Part d
Range
[tex]\lbrack0,\infty)[/tex]Part e
[tex]y=\sqrt[]{x-2}[/tex]