Question

Suppose a normal distribution has a mean of 79 and a standard deviation of 7. What is P(x ≤ 93)?A. 0.975B. 0.025C. 0.84D. 0.16

Answer 1

Answer:

A. 0.975

Explanation:

To determine P(x ≤ 93), we first find the z-score.

$\begin{gathered} Z-\text{Score}=\frac{X-\mu}{\sigma} \\ =\frac{93-79}{7} \\ =\frac{14}{7} \\ =2 \end{gathered}$

Therefore:

$P\begin{pmatrix}x\leqslant93\end{pmatrix}=0.975$