Question

what is the charge on each electrode after insulating handles are used to pull the electrodes away from each other until they are 1.0 cm apart?

Answer 1

Q1 = 1.66 958 x 10-14 C and Q2 = - 1.66 958 x 10-14 C are the charges on each electrode after the electrodes have been pulled apart by insulating handles until they are 1.0 cm apart.

Both the conventional current and the electrons move away from the anode. The negative charge of the anode can be inferred from both. The oxidation reaction taking place next to the anode is what generates the electron that enters it. Catalyzed [edit] In many ways, the cathode is the opposite of the anode is called as electrode.

delta V = 12V

we know Q = c* delta v where

C is capacitance of circular plate capacitor

NOW $C= EA/d$$= E\pi R^{2} /d$

 $Q = E\pi R^{2}(dv)/d$

NOW $E= 8.854 * 1o^{-12}$ $c^{2} /Nm^{2}$

R = 0.51/2 = 0.255 cm

d = 13cm =  0.13 m

Q = 8.854 x $10^{-12}$ x $\pi$ ( 2 . 5 5 - x 10 - 3 )/0.13 x 12

Q = 1.66958 x 10^{-14}C

SO Q1 , = 1 . 6 6 958 * 10^{-14} C

and / Q2 = - 1. 66 958 x 10^{-14}C

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