A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 100m long and 62m wide. Find the area of the training field. Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

At the end of the rectangular field, two semi-circles are used whose diameter is 62 meters, therefore, the radius of the circle is 31 meters(half of the diameter). The area of the semicircle can be written as,

[tex]\text{Area of 2 semicircles} = 2 \times \dfrac{\pi r^2}{2} = \pi r^2[/tex]

Area of 2 semicircles = π(r²) =π × (31²) = 3,019.07 m²

The area of the rectangle is the product of its length and its breadth. Therefore, the area of the rectangle will be,

Area of the rectangle = 100 × 62 =6,200 m²

Now, the area of the rectangular field is the sum of the area of the 2 semi-circles and the rectangle.

Area of the rectangular field= Area of the rectangle + Area of the Semi-circle

Area of the figure= 3,019.07 + 6200 = 9,219.07 m²

Hence, the area of the rectangular field is 9,219.07 m².

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