I need to substitute to solve each system of equations then, put in an a pair like this: ( )

System of Equations
Given the equations:
[tex]\begin{cases}y=4x-1 \\ y=2x-5\end{cases}[/tex]Solve it by substitution.
Since the y is isolated in both equations, we just substitute one into the other equation as follows:
[tex]2x-5=4x-1[/tex]Adding 5 and subtracting 4x:
[tex]\begin{gathered} 2x-4x=-1+5 \\ \text{Simplifying:} \\ -2x=4 \\ \text{Dividing by -2:} \\ x=-2 \end{gathered}[/tex]To find the value of y, just substitute x = -2 in any of the equations:
[tex]\begin{gathered} y=4(-2)-1 \\ y=-8-1 \\ y=-9 \end{gathered}[/tex]If we had used the second equation, we would have gotten the very same result.
Answer: (-2, -9)