Question

Given that sino =V50and coto is negative, determine and coto. Enter the angle O in degrees from the interval [0 ,360°). Write the exact answer.

Answer 1

It is given that

$\sin \theta=\frac{\sqrt[]{50}}{10}$

Then determining the value of theta,

$\theta=\sin ^{-1}\frac{\sqrt[]{50}}{10}=\sin ^{-1}\frac{7.07}{10}$$\theta=\sin ^{-1}0.7071068=45^{\circ}$

Then the value of theta is 45 degree but the value of cot theta is to negative so the theta is considered to 135 degree.

Now, we have to determine the value of

$\cot \theta=\cot 135^{\circ}=-1$