Given the equation;
[tex]6(2x-1)-12=3(7x+4)[/tex]let us expand the brackets and solve;
[tex]\begin{gathered} 6(2x-1)-12=3(7x+4) \\ 12x-6-12=21x+12_{} \\ -6-12-12=21x-12x \\ -30=9x \\ x=\frac{-30}{9} \\ x=-\frac{10}{3} \end{gathered}[/tex]Therefore, the value of x is;
[tex]x=-\frac{10}{3}[/tex]
