Question

(-8ab⁴)² Write your answer without parentheses.

Answer 1

Using the following property:

$(x^y)^z=x^{y\cdot z}$

so:

$\begin{gathered} (-8ab^4)^2=(-8)^2(a)^2(b^4)^2 \\ where\colon \\ (-8)^2=64 \\ (a)^2=a^2 \\ (b^4)^2=b^{4\cdot2}=b^8 \\ so\colon \\ (-8ab^4)^2=64a^2b^8 \end{gathered}$