Question

A technical machinist is asked to build a cubical steel tank that will hold 340 L of water.Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.01 m.

Answer 1

ANSWER:

0.7 m

STEP-BY-STEP EXPLANATION:

The first thing is to convert the liters to cubic meters, like this:

$340\text{ L}\cdot\frac{1000\text{ mL}}{1\text{ L}}\cdot\frac{1cm^3}{1\text{ mL}}\cdot\frac{1m^3}{1000000{}cm^3}=0.340m^3$

Volume of any cube = x^3,

where,

x = length of each side.

Therefore:

$\begin{gathered} x^3=0.340 \\ \text{ solving for x} \\ x=\sqrt[3]{0.340} \\ x=0.6979\cong0.70\text{ m} \end{gathered}$