Question

Enter the equation of the line in slope-intercept form.Slope is 7, and (5,3) is on the line.

Answer 1

We will replace those values in:

$y-y_1=m(x-x_1)$

That is:

$y-3=7(x-5)$

Then, we solve for y:

$\Rightarrow y-3=7x-35\Rightarrow y=7x-32$

From this, we have that the line that passes by the point (5, 3) and has a slope (m) of 7 is:

$y=7x-32$