Given:
The centre of the circle, (h,k)=(-5,0).
The radius of the circle, r =7.
Required:
We need to find the standard form of the equation of the circle.
Explanation:
Consider the standard form of the equation of the circle.
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h,k) is the centre and r is the radius.
Substitute h =-5, k=0 and r =7 in the equation.
[tex](x-(-5))^2+(y-0)^2=7^2[/tex][tex]Use\text{ \lparen-\rparen\lparen-\rparen=\lparen+\rparen and }7^2=49.[/tex][tex](x+5)^2+(y-0)^2=49[/tex][tex](x+5)^2+y^2=49[/tex]
Final answer:
The standard form of the equation of the circle with its centre at (- 5,0), and a radius of 7 is
[tex](x+5)^2+y^2=49.[/tex]
