Step-by-step explanation:
A has a density of 1.05 g/cm³
B has a density of 1.27 g/cm³
C has a density of x g/cm³
about the density of the resulting liquid C :
even before dealing with the full volume of the cylinder we can use the mixture ratio 4:11 to calculate the density of C.
we then simply assume that the ratio parts are actual volume parts to add the masses (g) :
4×1.05 + 11×1.27 = (4+11)×x
4.2 + 13.97 = 15x
18.17 = 15x
x = 1.211333333... g/cm³ (density of C)
now that we know that, let's calculate the volume of the cylinder. when we then multiply this volume with the density of C, then we know the mass (g) of C in the cylinder.
the volume of a cylinder is
V = pi×r²×h
r being the radius.
h being the height.
so, we have here :
V = pi×5²×20 = pi×25×20 = pi×500 cm³ =
= 1,570.796327... cm³
so, how many grams (g) of C are in that volume ?
1,570.796327... × 1.211333333... = 1,902.757951... g
≈ 1 900 g
(3 significant figures 1, 9, 0)
