Question

2x^2-8x-5=0Completing the square gives us: (x- Answer )^2 = AnswerEnter your solutions below from smallest to largest. If a solution is repeated type that answer for both values of x. If your answer is not an integer then type it as a decimal rounded to the nearest hundredth.x=Answer and x=Answer

Answer 1

The given equation is:

$2x^2-8x-5=0$

square is:

$\begin{gathered} 2x^2-8x-5=0 \\ 2x^2-8x=5 \\ x^2-4x=\frac{5}{2} \\ x^2-4x+4=\frac{5}{2}+4 \\ (x-2)^2=\frac{13}{2} \\ \end{gathered}$

Then the value of x:

$\begin{gathered} (x-2)^2=\frac{13}{2} \\ x-2=\pm\sqrt[]{\frac{13}{2}} \\ x=2\pm\sqrt[]{\frac{13}{2}} \\ x=2+\sqrt[]{\frac{13}{2}};x=2-\sqrt[]{\frac{13}{2}} \end{gathered}$