Initial speed of drop is given by
[tex]v_i = 50 ft/s[/tex]
total displacement of the object from top
[tex]d = 600 ft[/tex]
acceleration due to gravity
[tex]a = 31.5 ft/s^2[/tex]
so the final speed is given by kinematics equation
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
[tex]v_f^2 - 50^2 = 2 * 31.5 * 600[/tex]
[tex]v_f^2 - 2500 = 37800[/tex]
[tex]v_f^2 = 40300[/tex]
[tex]v_f = 200.7 ft/s[/tex]
so if will hit the surface at speed 200.7 ft/s