First, rewrite the fractions as improper fractions. Then, multiply the quantities to find the area of the rectangle.
[tex]4\frac{3}{7}=4+\frac{3}{7}=\frac{4\times7}{7}+\frac{3}{7}=\frac{28}{7}+\frac{3}{7}=\frac{31}{7}[/tex][tex]6\frac{4}{5}=6+\frac{4}{5}=\frac{6\times5}{5}+\frac{4}{5}=\frac{30}{5}+\frac{4}{5}=\frac{34}{5}[/tex]Then:
[tex]4\frac{3}{7}\times6\frac{4}{5}=\frac{31}{7}\times\frac{34}{5}=\frac{31\times34}{7\times5}=\frac{1054}{35}[/tex]Rewrite the fraction 1054/35 as a mixed fraction:
[tex]\frac{1054}{35}=\frac{1050}{35}+\frac{4}{35}=\frac{30\times35}{35}+\frac{4}{35}=30+\frac{4}{35}=30\frac{4}{35}[/tex]Therefore, if the dimentions of the rectangle are 4 3/7 and 6 4/5, then its area is equal to:
[tex]30\frac{4}{35}[/tex]
