One number is equal to the square of another. Find the numbers if both are positive and their sum is 1722
Let
x ------> one number
y -----> other number
we have that
x+y=1722
y=1722-x -------> equation A
x=√y -------> equation B
substitute equation A in equation B
x=√(1722-x)
squared both sides
x^2=1722-x
x^2+x-1722=0
solve by graphing
x=41
Find the value of y
y=1722-41
y=1681
therefore
the numbers are
41 and 1,681
