Based on the question, we are going to assume that the energy generated by brakes is going to transform into heat.
[tex]\begin{gathered} E=Q \\ E=\frac{mv^2}{2} \\ E=\frac{1000kg\cdot(\frac{90}{3.6}m/s)^2}{2} \\ E=312500J \\ \end{gathered}[/tex]Now we have to transform J into calories
[tex]312500J=74689.3\text{ }cal[/tex]