Recall that the point-slope form of a line is of the form y=mx+b. We are told that the point (4,1) is on our line and that the slope is 4. This means that m=4. So far, we have the equation
[tex]y=4x+b[/tex]So it only suffices to find the value of b.
Since (4,1) is on this line, it should happen that if we replace x by 4, it must happen that y is 1.
Then, we have the following
[tex]1=4\cdot4+b\text{ = 16+b}[/tex]So, if we subtract 15 on both sides, we get
[tex]b=1-16=-15[/tex]Then the equation of the line is
[tex]y=4\cdot x-15[/tex]