Question

${3x}^{4} {y}^{ - 2} x {2x}^{ - 1} {y}^{2}$whats the answer

Answer 1

$3x^4y^{-2}\times2x^{-1}y^2$$(3\times2)x^{4-1}y^{-2+2}$$6x^3y^0$$6x^3$

Multiply the numbers and combine exponents with the same base.