Given function is
[tex]f(t)=\frac{8t+4}{t+1}[/tex]
where t is in months after June 1st, 2002.
Substitute t=0 in the function, to find the initial population.
[tex]f(0)=\frac{8(0)+4}{(0)+1}[/tex]
[tex]f(0)=4\text{ million}[/tex]
The initial population of fruit flys on June 1st, 2002 is 4 million.
The graph of the given function is
We need to find the population after many months - for example, many years into the future.
Let us take t=100, and substitute in the given function, we get
[tex]f(100)=\frac{8(100)+4}{100+1}[/tex]
[tex]f(100)=\frac{804}{101}[/tex]
[tex]f(100)=7.96[/tex]
Round off, we get
[tex]f(100)=8[/tex]
Hence the population well into the future is 8 million.