Question

which value is a zero of the function defined by 6x^2+6x-36?

Answer 1

Only solve the equation:


$6x^2+6x-36=0\\ \\ \Delta=6^2-4.6.(-36)=36+864=900\\ \\ x=\frac{-6 \pm \sqrt{900}}{2.6}=\frac{-6 \pm30}{12}\\ \\ x_1=\frac{-36}{12}=-3\\ \\ x_2=\frac{24}{12}=2$

Zeros of this function are:  -3 and 2