Respuesta :

Part 1

Find out the area

The area of the given figure is equal to the area of a square of 6 x 6 units, minus the area of four right triangles of dimensions 3 x 3

so

[tex]A=6^2-4\cdot\lbrack\frac{1}{2}\cdot(3)\cdot(3)\rbrack[/tex][tex]\begin{gathered} A=36-18 \\ A=18\text{ unit2} \end{gathered}[/tex]

the area is 18 square units

Part 2

Find out the perimeter

The perimeter of the figure is equal to the hypotenuse of the right triangle (3 x 3 units) multiplied by 4

therefore

[tex]\begin{gathered} P=4\cdot\lbrack\sqrt[]{18}\rbrack \\ P=4\sqrt[]{18\text{ }}units \\ P=12\sqrt[]{2}\text{ units} \end{gathered}[/tex]

the perimeter is 16.97 units

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