Question

Point A is located at (-2,-4). The midpoint of the line segment AC is point B (6,8). What are the coordinates of point C ?

Answer 1

Answer:

Step-by-step explanation:

$Midpoint of AC = \left(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2} \right)\\\\x_{1}=-2 \ and \ y_{1}=-4\\\\\left(\dfrac{-2+x_{2}}{2},\dfrac{-4+y_{2}}{2} \right) = \left(6 ,8 \right)\\\\\\Compare \ x-coordinates \ and \ y-coordinates\\\\\dfrac{-2+x_{2}}{2}=6 \ ; \dfrac{-4+y_{2}}{2}=8$

-2 + x₂ = 6*2           ; -4 + y₂ = 8*2

-2 + x₂  = 12            ; -4 + y₂ = 16

        x₂ = 12+2        ;        y₂ = 16+4

        x₂ = 14            ;         y₂ = 20

Point C(14, 20)

Answer 2

Point C (14,20) this is the answer