Solution:
Given;
[tex]x=1280,\mu=1200,\sigma=45,n=780[/tex]Then, the z-score;
[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ \\ z=\frac{1280-1200}{45} \\ \\ z=\frac{80}{45} \\ \\ z=1.7778 \end{gathered}[/tex]Thus;
[tex]P(x<1.7778)=0.96228[/tex]Thus, the number of light bulbs that would be expected to last less than 1280 hours is;
[tex]\begin{gathered} 780(0.96228)=750.58 \\ \\ \approx751\text{ light bulbs} \end{gathered}[/tex]ANSWER: 751 light bulbs