Respuesta :
Answer: 40%
Step-by-step explanation:
Let A be the event that the athlete play baseball and B be the event that the athlete play basketball.
Given: The probability of athletes play baseball =[tex]P(A)=0.60[/tex]
The probability of athletes play baseball and basketball =[tex]P(B\cap A) = 0.24[/tex]
Then the probability that the athletes who play baseball also play basketball is given by :-
[tex]P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.24}{0.60}=0.4[/tex]
In percent , [tex]0.4\times100=40\%[/tex]
Hence, 40% of athletes who play baseball also play basketball.