Question

at the city museum child admission is $5.90 and adult admission is $9.90 on Tuesday twice as many adult tickets as child tickets were sold for a total sales of $745.30how many child tickets were sold that day

Answer 1

To find how many child tickets were sold on Tuesday you must first call:

X= number of child tickets

Y= number of adult tickets

Then you can propose the following equation:

Also, adult tickets sold were double of child tickets so

$Y=2\cdot X$

Replacing in the equation:

$\begin{gathered} X\cdot5.90\text{ + (2}\cdot X)\cdot9.90\text{ = 745.30} \\ X\cdot5.90\text{ + 19.80 }\cdot X\text{ = 745.30} \\ 25.70\cdot X\text{ = 745.30} \\ X=29 \\ Y=58 \end{gathered}$

So the child tickets sold that day were 29 tickets.