4 + 2(3x - 4) = 8
Distributing in the second term:
[tex]\begin{gathered} 4+2\cdot3x+2\cdot(-4)=8 \\ 4+6x-8=8 \\ 6x-4=8 \end{gathered}[/tex]Multiplying by 4/6 at both sides, we get:
[tex]\begin{gathered} \frac{4}{6}(6x-4)=\frac{4}{6}\cdot8 \\ \frac{4}{6}\cdot6x-\frac{4}{6}\cdot4=\frac{32}{6} \\ 4x-\frac{16}{6}=\frac{16}{3} \\ 4x-\frac{8}{3}=\frac{16}{3} \\ 4x=\frac{16}{3}+\frac{8}{3} \\ 4x=\frac{24}{3} \\ 4x=8 \end{gathered}[/tex]Subtracting 4 at both sides:
[tex]\begin{gathered} 4x-4=8-4 \\ 4x-4=4 \end{gathered}[/tex]Then, 4 is the correct choice
