Respuesta :
Answer:
The answer to your question is letter C
Step-by-step explanation:
Data
hamburgers = h
fries = f
soda = s
Student 1 4h + 4f + 1s = 21
Student 2 1h + 1f + 1s = 5
Student 3 1h + 1f = 5
From the data of students 2 and 3 we can conclude that the system will not have a solution because is not possible that one student has charged 3 items for the same cost of student 3 that bought only 2 items.
As per the text, 3 students buy the lunch n cafeteria and 1 student buys 4 hamburgers, 4 tries, and one soda, for 21$. Another student buys one hamburger, 1 tries, 1 soda for 5 dollars. The third one buys in the burger and $5 of fries.
- As per Student 1 equals to 4h + 4f + 1s = 21
- As per Student 2 equals to 1h + 1f + 1s = 5
- As per Student 3 equals to 1h + 1f = 5
Hence the correct option is C.
Learn more about the students who buy lunch in the cafeteria One student buys 4 hamburgers.
brainly.com/question/16024284.