4a. Explain how we can tell that this graph represents the give


a) the slope is 250
b)for every mile ( along thail) the hikers progress 250 meters ( elevation)
c)y=250x+500
3d)yes, the equation y-250x=500 represents the same relationship
Explanation
Step 1
slope of the line.
the slope of a line is given by the expression
[tex]\begin{gathered} slope=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1)\text{ and} \\ P2(x_2,y_2) \\ are\text{ 2 points from the line} \end{gathered}[/tex]then
pick up two poins from the line
[tex]\begin{gathered} \text{let} \\ P1(0,500) \\ P2(2,1000) \end{gathered}[/tex]replace in the expression
[tex]\begin{gathered} slope=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{1000-500}{2-0}=\frac{500}{2}=250 \end{gathered}[/tex]so, the slope is 250
Step 2
what does the slope tell use about this situation
as the slope is rate of change
[tex]\begin{gathered} slope=\frac{\Delta y}{\Delta x} \\ \text{replace the units ( check the a}\xi s) \\ \text{slope}=\text{ 250}\frac{ft}{\text{miles}} \end{gathered}[/tex]so, the slope tell us
for every mile ( along thail) the hikers progress 250 meters ( elevation)
Step 3
equation:
to find the equation we can use the point slope equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{where m is the slope} \\ \text{and} \\ P1(x_1,y_1) \end{gathered}[/tex]replace
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-500=250(x-0) \\ y-500=250x \\ \text{add 500 in both sides} \\ y=250x+500 \end{gathered}[/tex]Step 4
finally.
Does the equation y-250x=500 represent the same relationship?
if we start from
[tex]y=250x+500[/tex]then, we apply the subtraction property of equality ( which does not affect the function)
so
subtract 250 x in both sides
[tex]\begin{gathered} y=250x+500 \\ \text{subtract 250 x in both sides} \\ y-250x=250x+500-250x \\ y-250x=500 \end{gathered}[/tex]so
yes, the equation y-250x=500 represents the same relationship
I hope this helps you