The angles given are
[tex]\sin a=\frac{5}{13},\cos b=\frac{3}{5}[/tex]Determine the value of cos a
[tex]\cos a=\sqrt[]{1-\frac{25}{169}}=\frac{12}{13}[/tex]Determine the value of sin b
[tex]\sin b=\sqrt[]{1-\frac{9}{25}}=\frac{4}{5}[/tex]The value of tan a is
[tex]\tan \text{ a=}\frac{\frac{5}{13}}{\frac{12}{13}}=\frac{5}{13}\times\frac{13}{12}=\frac{5}{12}[/tex]The value of tan b is
[tex]\tan b=\frac{\frac{4}{5}}{\frac{3}{5}}=\frac{4}{3}[/tex]The value of tan(a-b) is
[tex]\tan (a-b)=\frac{\tan a-tanb}{1+\tan a\tan b}[/tex][tex]\tan (a-b)=\frac{\frac{5}{12}-\frac{4}{3}}{1+\frac{5}{12}\times\frac{4}{3}}=\frac{\frac{5-16}{12}}{1+\frac{5}{9}}=\frac{\frac{-11}{12}}{\frac{14}{9}}=-\frac{11}{12}\times\frac{9}{14}=-\frac{11}{4}\times\frac{3}{14}=-\frac{33}{56}[/tex][tex]\tan (a-b)=-\frac{33}{56}[/tex]Hence the correct option is 2.