graph the line passing through 2 and -2 with a slope m equals 4/3

We have the following:
The first thing we must do is calculate the equation and then graph:
We have that the equation the equation of the line would be:
[tex]y-y_0=m\cdot(x-x_0)[/tex]replacing:
[tex]\begin{gathered} y-(-2)=\frac{4}{3}\cdot(x-2) \\ y+2=\frac{4}{3}x-\frac{8}{3} \\ y=\frac{4}{3}x-\frac{14}{3} \end{gathered}[/tex]We graph:
Points must be at (2,-2) and (8, 6)