Question

What is the molarity of a solution when 1.55moles of NaBr is dissolved in 950mL of solution?

Answer 1

Step 1

Molarity can be defined as follows:

$Molarity\text{ \lparen M or mol/L\rparen = }\frac{Numberofmolesofsolute}{Volume\text{ of solution \lparen L\rparen}}=\text{ }\frac{n}{V(L)}$

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Step 2

Data provided:

1.55 moles of NaBr (solute)

950 mL of solution

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Step 3

Procedure:

From step 1,

Turn 950 mL into L:

V = 950 mL

1 L = 1000 mL, so V = 950 mL = 0.950 L

V = 0.950 L

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Then,

Molarity = n/V(L) = 1.55 moles/0.950 L

Molarity = 1.63 mol/L

Answer: Molarity = 1.63 mol/L or M