we know that
the volume of the cone is equal to
[tex]V=\frac{1}{3}\cdot\pi^{}\cdot r^2\cdot h[/tex]we have
pi=3.14
r=13 cm
h=16 cm
substitute
[tex]\begin{gathered} v=\frac{1}{3}\cdot3.14\cdot(13^2)\cdot16 \\ v=2,830.2\text{ cm\textasciicircum{}3} \end{gathered}[/tex]