Answer:
1669.78 km/hr
Explanation:
Equator size of the circle = 2πr
os λ = 2x3.14x6378.1x
Cos 0= 2x3.14x6378.1x1 =40074.78 km
Now velocity at equator = Size of the circle ÷ Time = 40074.78 ÷ 24 = 1669.78 km/hr.
Hence the person standing at the equator will be moving at a speed of 1669.78 km/hr.