The volume of calcium sulfate 0.00747 mol/L is 147 L ( rounding 3 significant digits.
Since we're trying to find the volume and we don't have moles to directly work with, the best thing to do first is to convert the 150. g of CaSO4 to moles.
We can do this by dividing by the molar mass of CaSO4
Molar mass of CaSO4 = 136.14 g/mol
This means that 1 mole of CaSO4 = 136.14 g of CaSO4
Using this relationship, we can calculate the no. of moles in 150.g by dividing by the molar mass
150. g x 1 mol/136.14 g = 1.10 moles
Using the relationship that 0.00747 moles of CaSO4 in 1L of solution, we can calculate the volume that has 1.10 mols of CaSO4
We divide by the molarity 1.10 mols CaSO4 x 1L/0.00747 mols CaSO4 = 147 L
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