Question

Can anyone please solve this? I need it to be right.

Answer 1

Answer:

65

Step-by-step explanation:

$\frac{3(2^5)-13(-2)+2^3}{-2^2+3^2-3} =\frac{3(32)+26+(8)}{(-4)+(9)-3} =\frac{96+34}{2} =\frac{130}{2}=65$