A car that travels 5 km due east and makes a U turn to travel another 7 km. If the time taken for the whole journey is 0.2 h. Calculate the (a) average speed (b) average velocity of the car.​

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Answer:

10 miles/hr East

Explanation:

The car travels 5 miles East and then reverses direction. It then travels 7 miles in the reverse direction, arrive at the point it started, and going 2 miles further West of the start point. The time elapsed for this trip was 0.2 hours.

The net change in position is 2 miles East, in 0.2 hours. The average velocity is thus (2 miles E)/(0.2 hr) = 10 miles/hr East

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