Respuesta :

The density of a sample of rubbing alcohol if it has a specific gravity of 0.789 the density of water is 1.000 g/ml will be 789 kg/m3.

Specific gravity was the proportion of a substance's density (mass per unit volume) to particular reference material, frequently a liquid. Specific gravity equals a substance's density (g/mL). Water density (g/mL) for the same temperature

Specific gravity can be calculated as:

Specific gravity = density of substance / density of water

0.789  = density of substance  / 1000 kg/m3

density of substance = 0.789 × 1000 kg/m3

density of substance = 789 kg/m3.

Therefore, the density of a sample of rubbing alcohol if it has a specific gravity of 0.789 the density of water is 1.000 g/ml will be 789 kg/m3.

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