Question

Bryan's Boutique sells shirts, skirts, shoes and hats. If Bryan sells 3 types of shirts, 6 types of skirts, 8 types of bracelets and 2 types of hats, how many different outfits can a customer put together if an outfit must include one shirt, one skirt, one bracelet and one hat?

Answer 1

Using the Fundamental Counting Theorem, it is found that the customer can put together 288 different outfits.

What is the Fundamental Counting Theorem?

It is a theorem that states that if there are n things, each with $n_1, n_2, \cdots, n_n$ ways to be done, each thing independent of the other, the number of ways they can be done is:

$N = n_1 \times n_2 \times \cdots \times n_n$

Bryan sells 3 types of shirts, 6 types of skirts, 8 types of bracelets and 2 types of hats, hence the parameters are given as follows:

$n_1 = 3, n_2 = 6, n_3 = 8, n_4 = 2$

Hence the number of different outfits is given as follows:

N = 3 x 6 x 8 x 2 = 288

More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866

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