The sequence of the ball is 3, 1, 1/3, 1/9,...
The ball starts bouncing with a height of 3 feet.
Each bounce reaches a third of the height of the previous bounce.
Therefore,
a = first term = 3
r = common ratio = 1 / 3
Therefore,
nth term = arⁿ⁻¹
where
First term = 3
2nd term = 3 × (1 / 3) = 1
Third term = 3 × (1 / 3)² = 1 / 3
Fourth term = 3 × (1 / 3)³ = 1 / 9
Therefore, the sequence of the ball is 3, 1, 1/3, 1/9,...
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