Question

Write an algebraic expression for each statement:

a. The value of a three digit number if the tens digit is c, the hundreds digit is three less than the tens and the ones digit is 0?
b. The tens digit of a number is b and the units digit is twice as big. What is the value of the number in terms of b if the digits are reversed?

I hope you can help me with these questions!!

Answer 1

For the given sentences, the algebraic expressions are:

a) N = 110*c - 300

b) N = 12*b

How to get the algebraic expressions?

For the first statement:

A 3-digit number, where the tens digit is c, can be written as:

N = 100*a + 10*c + b

Then the hundreds digit is a, and here we know that is 3 less than the tens digit, then:

a = c - 3

The ones digit is b, here we know that it is 0, then b = 0.

Replacing that in our number we get:

N = 100*(c - 3) + 10*c = 110*c - 300

N = 110*c - 300

That is the algebraic expression.

b) A two-digit number can be written as:

N = b*10 + a

Where b is the tens digit and a is the ones digit.

Here we know that the units digit is twice as bit as the tens digit, then:

a = 2b

Replacing that we get:

N = b*10 + a = b*10 + 2b = 12*b

N = 12*b

That is the algebraic expression.

If you want to learn more about algebraic expressions:

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