100 POINTS!! Find the indicated angle or side. Give an exact answer.
Find the measure of angle A in degrees.
![100 POINTS Find the indicated angle or side Give an exact answer Find the measure of angle A in degrees class=](https://us-static.z-dn.net/files/d53/0d35a8bdd04463ea2a82d405d12df7e0.jpg)
Answer:
A = 120
Step-by-step explanation:
To find angle A we will need to use the law of cosines, since we know the three sides of the triangle.
a^2=b^2+c^2−2*b*c*cosA
(2 sqrt(13)) ^2 = 6^2 + 2^2 + 2 * 6 * 2 cos A
4*13 = 36 + 4 - 24 cos A
52 = 40- 24 cos A
12 = -24 cos A
-1/2 = cos A
Take the inverse cos of each side
cos^-1(-1/2) = cos^-1(cos A)
120 = Cos A or 240 = Cos A
A cannot be greater than 180 so A = 120
Answer:
A = 120°
Step-by-step explanation:
We can use the cosine rule to solve for angle A, since lengths of all sides are known:
[tex]a^2 = b^2+ c^2 - 2(b)(c) \space\ cos A[/tex]
where a, b, and c are the sides opposites angles A, B, and C respectively.
∴ a = 2√3 , b = 6, c = 2
• Rearranging the formula to make A the subject:
[tex]2(b)(c) \space\ cos A = b^2 + c^2 -a^2[/tex]
⇒ [tex]cos A = \frac{b^2 + c^2 -a^2}{2(b)(c)}[/tex]
⇒ [tex]A = cos^{-1}(\frac{b^2 + c^2 -a^2}{2(b)(c)} )[/tex]
• Now we can substitute the values into the equation to calculate the value of angle A:
[tex]A = cos^{-1}(\frac{6^2 + 2^2 -(2\sqrt{13})^2}{2(6)(2)} )[/tex]
⇒ [tex]A = cos^{-1} (-\frac{1}{2} )[/tex]
⇒ A = 120°