Question

The value of $\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)-\sin ^{-1}\left(\frac{1}{2}\right)$ is​

Answer 1

Answer:

$\displaystyle \frac{\pi}{6}$

Explanation:

According to the unit circle, $\displaystyle \frac{\pi}{3}$ and $\displaystyle \frac{\pi}{6}$ are the radian measures you are looking for because all y-coordinates are associated with the sine function, so when evaluating, you will arrive at this:

$\displaystyle \boxed{\frac{\pi}{3}} = \frac{\pi}{3} - \frac{\pi}{6}$

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