Question

(sec x + tan x)((1-sin x/cos x)=1 Please show calculations why you did those calculations. I need help!!!

Answer 1

Step-by-step explanation:

$( \sec(x) + \tan(x) )( \frac{1 - \sin(x) }{ \cos(x) } )$

$( \frac{1}{ \cos(x) } + \frac{ \sin(x) }{ \cos(x) } )( \frac{1 - \sin(x) }{ \cos(x) } )$

$( \frac{1 + \sin(x) }{ \cos(x) } )( \frac{1 - \sin(x) }{ \cos(x) } )$

$\frac{1 - \sin {}^{2} (x) }{ \cos {}^{2} (x) }$

$\frac{ \cos {}^{2} (x) }{ \cos {}^{2} (x) }$

$= 1$