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The [H+ ] and pH of a 0.400 M solution of hypobromous acid are mathematically given as

  • H+=3.35*10^{-5}M
  • pH=4.575

What is the [H+ ] and pH of a 0.400 M solution of hypobromous acid?

Generally, the equation for Chemical Reaction is mathematically given as

HBrO---><----H+BrO

Therefore

[tex]Ka-\frac{H+[BrO-]}{[-HBro-]}\\\\ 2.8 x 10-9 =\frac{x.x}{0.400-x}\\\\x=3.35*10^{-5}M\\\\[/tex]

In conclusion, the pH value is

pH=-log(h+)

pH=-log(3.35*10^{-5}M)

pH=4.575

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