The [H+ ] and pH of a 0.400 M solution of hypobromous acid are mathematically given as
Generally, the equation for Chemical Reaction is mathematically given as
HBrO---><----H+BrO
Therefore
[tex]Ka-\frac{H+[BrO-]}{[-HBro-]}\\\\ 2.8 x 10-9 =\frac{x.x}{0.400-x}\\\\x=3.35*10^{-5}M\\\\[/tex]
In conclusion, the pH value is
pH=-log(h+)
pH=-log(3.35*10^{-5}M)
pH=4.575
Read more about Chemical Reaction
https://brainly.com/question/11231920
#SPJ1