Question

Renate launched an object vertically from a point that is 58.9 meters above ground level with an initial velocity of 21.6 meters per second. This situation can be represented by the equation h=−4.9t2+21.6t+58.9, where h is the height of the object in meters and t

is the time in seconds after the object is launched.

What is the maximum height of the object?

Answer 1

The maximum height of the object is 82.7034 from the ground

What is Velocity ?

Velocity is the measure of movement of an object with respect to time.

It is measured in m/sec

h = -4.9t²+21.6t +58.9

dh/dt = -9.8t +21.6

At maximum height ,  velocity = 0

therefore

-9.8t +21.6 = 0

9.8t = 21.6

t = 2.204 sec

h = -4.9 (2.204)²+ 21.6 * 2.204 +58.9

h = -23.803  +47.606 +58.9

h = 82.7034 from the ground

h = 23.80 from the point it is launched.

The maximum height of the object is 82.7034 from the ground

To know more about Velocity

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