jakileti007 jakileti007

26-06-2022
SAT

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If x+4 is a factor of x^2-ax-12a and a is a constant, what is the value of a?

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sithai2203 sithai2203

26-06-2022

Answer:

[tex]x^{2} -ax-12a=(x+4)(x-4-a)-8a+16\\x+4 is a factor of x^2-ax-12a\\-8a+16=0\\a=2[/tex]

Explanation:

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